SOLUTION: Find the exact value of sin(a+b), given that sin a=-4/5 and cos b = 12/13, with a in quadrant III and b in quadrant IV
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Question 1127103: Find the exact value of sin(a+b), given that sin a=-4/5 and cos b = 12/13, with a in quadrant III and b in quadrant IV Answer by ikleyn(52794) (Show Source):
Use the formula
sin(a+b) = sin(a)*cos(b) + cos(a)*sin(b) (1)
Regarding this formula, see the lesson Addition and subtraction formulas in this site.
In addition to the given sin(a) = and cos(b) = , you need to know cos(a) and sin(b).
1. cos(a) = = = = = = - =-.
The sign "-" was chosen for the square root because cos(a) is negative when the angle "a" is in QIII.
2. sin(b) = = = = = = = -.
The sign "-" was chosen for the square root because sin(b) is negative when the angle "b" is in QIV.
Now all you need to do is to substitute everything into the formula (1) and make the calculations.
sin(a+b) = = = = . ANSWER