SOLUTION: To a motor-cyclist traveling due north at 50km/hr, the wind appear to come from north west at 60km/hr, what is the true velocity of the wind

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Question 1127027: To a motor-cyclist traveling due north at 50km/hr, the wind appear to come from north west at 60km/hr, what is the true velocity of the wind
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
1.  Let's consider more simple case first:


        Let there is no wind at the coordinate system which rests relative the Earth,
        and a motor-cyclist travels due North at 50 km/h.


    Then it is clear that he/she will observe the wind due to south at 50 km/h.

    I other words, he/she will observe the wind with the vector  (0,-50)  (the units of speed are in km/h).



2.  Then it is clear, that if there is the wind with the velocity vector  W 
    
    in the coordinate system which rests relative the Earth surface, and 

    the motor-cyclist moves at the speed  M  (! M is vector !), then the wind he/she will observe is W%5Bobserved%5D = W - M.



3.  With these explanations, we have 


        - the vector  M = (0,50) of the motor-cyclist speed relative the Earth;

        - the vector  W%5Bobserved%5D = (60%2A%28sqrt%282%29%2F2%29,-60%2A%28sqrt%282%29%2F2%29)

         - and the equation  W%5Bobserved%5D = (60%2A%28sqrt%282%29%2F2%29,-60%2A%28sqrt%282%29%2F2%29) = W - (0,50).


    From this equation, the "real" vector of the wind velocity in the resting coordinate system is


        W = (60%2A%28sqrt%282%29%2F2%29,-60%2A%28sqrt%282%29%2F2%29) + (0,50) = (60%2A%28sqrt%282%29%2F2%29,-60%2A%28sqrt%282%29%2F2%29%2B50).


    Now, when you know the vector W by its components, you can easily calculate its magnitude.


    It is just arithmetic, and I leave it to you to complete this assignment on your own.


So, by explaining all these details to you, I consider my function as a tutor fully completed.