SOLUTION: Write the equation below as one involving only sinθ and cosθ.
sin2θ+cosθ
It's not supposed to equal anything, that's how it is on my homework. I don't u
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-> SOLUTION: Write the equation below as one involving only sinθ and cosθ.
sin2θ+cosθ
It's not supposed to equal anything, that's how it is on my homework. I don't u
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Question 1101648: Write the equation below as one involving only sinθ and cosθ.
sin2θ+cosθ
It's not supposed to equal anything, that's how it is on my homework. I don't understand how to do this and am overall confused with trig addition and subtraction. Thanks! Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Make it sin and cos of t, not of 2t.
sin(2t) = 2sin(t)*cos(t)
--> 2sin(t)*cos(t) + cos(t)
That's all.
