Question 1099756: Use the coodinates of the five quarter points of y=sin x to determine the corresponding quarter points on the graph of y=sin(3x-π)
Quarter points of y = sin x: (0,0) (π/2 ,1) (π,0) (3π/2, -1) (2π,0)
Quarter points of y = sin (3x-π):
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Use the coodinates of the five quarter points of y=sin x to determine the corresponding quarter points on the graph of y=sin(3x-π)
Quarter points of y = sin x: (0,0) (π/2 ,1) (π,0) (3π/2, -1) (2π,0)
Quarter points of y = sin (3x-π):
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You need the graphs to do that.
DL the FREE graph software at
www.padowan.dk
Use Ins, enter sin(x), then sin(3x - pi)
Use different colors for clarity, and change the x-axis to "multiple of pi"
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