SOLUTION: Tanxsin^2x=1.21tanx

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Question 1084174: Tanxsin^2x=1.21tanx
Answer by ikleyn(53763) About Me  (Show Source):
You can put this solution on YOUR website!
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The only solution in the interval [0,2pi) are x= 0 ans x= pi.


The solutions on the number line are x = k%2Api, k = 0, +/-1, +/-2, . . . 



The steps:


tan%28x%29%2Asin%5E2%28x%29 = 1.21%2Atan%28x%29  ====>

tan%28x%29%2Asin%5E2%28x%29+-+1.21%2Atan%28x%29 = 0  ====>

tan%28x%29%2A%28sin%5E2%28x%29+-+1.21%29 = 0.


The term (sin^2(x) - 1.21) is NEVER zero.


Therefore, the only solutions come from tan(x) = 0.

Solved.