SOLUTION: Find the area of the shaded figure, rounded to two decimals. (Assume x = 2 and y = 6.)
http://www.webassign.net/sprecalc6/6-6-034-alt.gif
link to figure
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-> SOLUTION: Find the area of the shaded figure, rounded to two decimals. (Assume x = 2 and y = 6.)
http://www.webassign.net/sprecalc6/6-6-034-alt.gif
link to figure
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Question 1080607: Find the area of the shaded figure, rounded to two decimals. (Assume x = 2 and y = 6.)
http://www.webassign.net/sprecalc6/6-6-034-alt.gif
link to figure Found 3 solutions by Boreal, MathLover1, MathTherapy:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! If y is the side
the area is 5 parts, the area of the base, x^2=4, plus 4 times the area of the faces. The height of a face is a straight line drawn to bisect the base. The triangle formed has hypotenuse 6, base 1 (bisected), and altitude sqrt (35). (Pythagorean theorem 1^2+x^2=6^2)
The area of each face is (1/2)bh=(1/2)*2* sqrt (35)=sqrt (35)
There are 4 of them so the area of the faces collectively is 4 sqrt (35)=23.66
Add to that the 4 above and the area is 27.66.
You can put this solution on YOUR website! given: and and two equilateral triangles
You have two equilateral triangles (you know this since two of the three sides have a length of "" in each triangle.
Both triangles are the same.
To get the area, we need to know the height. We know the base is , but not the height.
Altitude of the shaded isosceles triangle: .......... and
Surface area of the shaded one isosceles triangle:
Surface area of the whole shaded figure:
so, .............plug in values for and
