Question 1075860: please help me solve this
using substitution y=3^X, solve the equation 3^x=2+3^-x. Found 2 solutions by ikleyn, Alan3354:Answer by ikleyn(52788) (Show Source):
After substituting y = , your equation becomes
y =
Multiply by "y" both sides. You will get
= , or
= 0.
Apply the quadratic formula to solve the quadratic equation. You will get
= = = .
The negative root does not make sense, since y = must be positive.
It is EXTRANEOUS root for our problem.
The only positive root y = survives.
So, we have = , which implies
x = .
You can put this solution on YOUR website! solve the equation 3^x=2+3^-x.
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3^x = 2 + 3^-x
3^x - 2 - 3^-x = 0
Mutliply thru by 3^x
3^(2x) - 2*3^x - 1 = 0
Sub y for 3^x
y^2 - 2y - 1 = 0