SOLUTION: if an equilateral triangle is circumscribed about a circle of radius 10cm. determine the side of the triangle?

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Question 1052636: if an equilateral triangle is circumscribed about a circle of radius 10cm. determine the side of the triangle?

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The circle and equilateral triangle can be slices pizza-style into 6 wedges/triangles.

The right triangle shown above is one of those 6 triangles.
It is a right triangle because the radius of the circle must be perpendicular to the tangent side of the equilateral triangle.
The angle at the center of the circle is 360%5Eo%2F6=red%2860%5Eo%29 .
The side adjacent to that angle is the radius of the circle, and measures 10cm .
The opposite side, of length x , is 1%2F2 of the side of the equilateral triangle.
The trigonometric ratios tell us that
x%2F%2210+cm%22=tan%2860%5Eo%29=sqrt%283%29=about1.73 ,
so x=10sqrt%283%29cm=about17.3cm and 2x=highlight%2820sqrt%283%29%29cm=highlight%28about34.6cm%29 is the length of the side of the equilateral triangle.

Allergic to trigonometry? Then, you would have to use similar triangles and the Pythagorean theorem.
Right triangles BCD and OAD are similar because their smallest angles are congruent. (Angles BCD and OAD are both half of an equilateral triangle's angle).
AD=DC=x is half of the equilateral triangle's side.
AC=BC=2x is the equilateral triangle's side.
Since the triangles are similar, the ratio of long leg to short leg is
AD%2FDO=CD%2FBC or x%2F%2210+cm%22=CD%2Fx ---> x%5E2=CD%2A10cm
We can find CD, the long leg of BCD, using the Pythagorean theorem, because
CD%5E2%2BDC%5E2=BC%5E2 or CD%5E2%2Bx%5E2=%282x%29%5E2 , and
CD%5E2%2Bx%5E2=%282x%29%5E2-->CD%5E2%2Bx%5E2=4x%5E2-->CD%5E2=3x%5E2-->CD=sqrt%283%29x .
So, plugging that into x%5E2=CD%2A10cm , we get
x%5E2=sqrt%283%29x%2A10cm--->x=sqrt%283%29%2A10cm
So the side of the equilateral triangle measures AC=2x=2sqrt%283%29%2A10cm=highlight%28sqrt%283%29%2A20cm=about+34.6cm%29