SOLUTION: cos(2x-pi/6) = sqrt3/2 solve the equation on the interval [0,2pi).

Algebra ->  Trigonometry-basics -> SOLUTION: cos(2x-pi/6) = sqrt3/2 solve the equation on the interval [0,2pi).      Log On


   

Question 1051496: cos(2x-pi/6) = sqrt3/2
solve the equation on the interval [0,2pi).
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Where the cosine is equal to sqrt(3)/2 is at pi/6 and 11pi/6.
Set 2x-pi/6=pi/6.
2x=2pi/6
x=pi/6
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Set 2x-pi/6=11pi/6
2x=12pi/6
x=pi-----(6pi/6)