SOLUTION: Solve the triangle ABC. (using the law of cosines) a=10,b=12,c=16

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Question 1042353: Solve the triangle ABC. (using the law of cosines)
a=10,b=12,c=16

Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the triangle ABC. (using the law of cosines)
a=10,b=12,c=16
===================
You should do that.
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The Cosine Law is similar to the Pythagorean Theorem.
---
c^2 = a^2 + b^2
--
Add 1 term:
c^2 = a^2 + b^2 - 2ab*cos(C)
------------
Notice that angle C = 90 degs in a right triangle --> 2ab*0 --> Pythagoras.

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Solve the triangle ABC. (using the law of cosines)
a=10,b=12,c=16
~~~~~~~~~~~~~~~~~~~~

This assignment is to find the angles of the given triangle.

Use the Law of Cosines.

c%5E2 = a%5E2+%2B+b%5E2+-+2ab%2Acos%28C%29,   or

16%5E2 = 10%5E2+%2B+12%5E2+-+2%2A10%2A12%2Acos%28C%29,   or

256 = 100 + 144 - 240*cos(C),   or

256 - 100 - 144 = - 240*cos(C),   or

12 = -240*cos(C),   or

cos(C) = -12%2F240 = -1%2F20.   --->  angle C = arccos%28-1%2F20%29+%2B+pi = pi+-+arccos%281%2F20%29   (an obtuse angle).

Doing by the same way, find cos(B) and cos(C).

This is the way.