SOLUTION: Suppose tan(alpha) = {{{5/6}}} and alpha terminates in Quadrant III. Without simplifying any square roots, sin(alpha) = cos(alpha) = cot(alpha) = sec(alpha)

Algebra ->  Trigonometry-basics -> SOLUTION: Suppose tan(alpha) = {{{5/6}}} and alpha terminates in Quadrant III. Without simplifying any square roots, sin(alpha) = cos(alpha) = cot(alpha) = sec(alpha)       Log On


   



Question 1022333: Suppose tan(alpha) = 5%2F6 and alpha terminates in Quadrant III.
Without simplifying any square roots,
sin(alpha) =
cos(alpha) =
cot(alpha) =
sec(alpha) =
csc(alpha) =

Found 3 solutions by Alan3354, ikleyn, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
Suppose tan(alpha) =  5%2F6 and alpha terminates in Quadrant III.
Without simplifying any square roots, calculate 


sin(alpha) =  -tan%28alpha%29%2Asqrt%281%2F%281+%2B+tan%5E2%28alpha%29%29%29 = -%285%2F6%29%2Asqrt%281%2F%281+%2B+%285%2F6%29%5E2%29%29 = -%285%2F6%29%2Asqrt%2836%2F%2825%2B36%29%29 = -5%2Fsqrt%2861%29%29.
               
              The sign "-" (minus) was chosen because the angle alpha terminates in Quadrant III.

               
cos(alpha) =  -sqrt%281%2F%281+%2B+tan%5E2%28alpha%29%29%29 = -sqrt%281%2F%281+%2B+%285%2F6%29%5E2%29%29 = -sqrt%2836%2F%2825%2B36%29%29 = -6%2Fsqrt%2861%29%29.


              The sign "-" (minus) was chosen because the angle alpha terminates in Quadrant III.


cot(alpha) =  1%2Ftan%28alpha%29 = 6%2F5.


sec(alpha) =  1%2Fcos%28alpha%29 = -sqrt%2861%29%2F6.


csc(alpha) =  1%2Fsin%28alpha%29 = -sqrt%2861%29%2F5.

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Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose tan(alpha) = 5%2F6 and alpha terminates in Quadrant III.
Without simplifying any square roots,
sin(alpha) =
cos(alpha) =
cot(alpha) =
sec(alpha) =
csc(alpha) =
tan+%28alpha%29+=+5%2F6+=+%28-+5%29%2F%28-+6%29+=+y%2Fx
r%5E2+=+x%5E2+%2B+y%5E2______r%5E2+=+%28-+6%29%5E2+%2B+%28-+5%29%5E2_____r%5E2+=+36+%2B+25____r+=+sqrt%2861%29
sin%28alpha%29+=+y%2Fr+=+%28-+5%29%2Fsqrt%2861%29+=+%28-+5sqrt%2861%29%29%2F61
cos%28alpha%29+=+x%2Fr+=+%28-+6%29%2Fsqrt%2861%29+=+%28-+6sqrt%2861%29%29%2F61
cot%28alpha%29+=+x%2Fy+=+%28-+6%29%2F%28-+5%29+=+6%2F5
sec%28alpha%29+=+r%2Fx+=+sqrt%2861%29%2F%28-+6%29+=+-+sqrt%2861%29%2F6
csc%28alpha%29+=+r%2Fy+=+sqrt%2861%29%2F%28-+5%29+=+-+sqrt%2861%29%2F5