SOLUTION: Suppose tan(alpha) = {{{5/6}}} and alpha terminates in Quadrant III.
Without simplifying any square roots,
sin(alpha) =
cos(alpha) =
cot(alpha) =
sec(alpha)
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-> SOLUTION: Suppose tan(alpha) = {{{5/6}}} and alpha terminates in Quadrant III.
Without simplifying any square roots,
sin(alpha) =
cos(alpha) =
cot(alpha) =
sec(alpha)
Log On
Suppose tan(alpha) = and alpha terminates in Quadrant III.
Without simplifying any square roots, calculate
sin(alpha) = = = = .
The sign "-" (minus) was chosen because the angle terminates in Quadrant III.
cos(alpha) = = = = .
The sign "-" (minus) was chosen because the angle terminates in Quadrant III.
cot(alpha) = = .
sec(alpha) = = .
csc(alpha) = = .
You can put this solution on YOUR website! Suppose tan(alpha) = and alpha terminates in Quadrant III.
Without simplifying any square roots,
sin(alpha) =
cos(alpha) =
cot(alpha) =
sec(alpha) =
csc(alpha) =