SOLUTION: Recall that for triangle ABC the law of sines states that (sin A)/a= (sin B)/b= (sin C)/c. If angle A= 30, angle B= 45, and a= 16, find b. A. Square root of 2 B. 4 times the

Algebra ->  Triangles -> SOLUTION: Recall that for triangle ABC the law of sines states that (sin A)/a= (sin B)/b= (sin C)/c. If angle A= 30, angle B= 45, and a= 16, find b. A. Square root of 2 B. 4 times the       Log On


   



Question 620557: Recall that for triangle ABC the law of sines states that (sin A)/a= (sin B)/b= (sin C)/c. If angle A= 30, angle B= 45, and a= 16, find b.
A. Square root of 2
B. 4 times the square root of 2
C. the square root of 2 divided by 32
D. 16 times the square root of 2
I know the answer is D. but i do not know how to reach that solution.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
(sin A)/a= (sin B)/b

(sin(30))/16 = (sin(45))/b

(1/2)/16 = (sqrt(2)/2)/b

(1/2)*b = 16*sqrt(2)/2

b/2 = 8*sqrt(2)

b = 2*8*sqrt(2)

b = 16*sqrt(2)