SOLUTION: The diameter of a ferris wheel is 80 feet.
a) if the ferris wheel make one revolution every 45 seconds, find the linear velocity of a person riding in the ferris wheel.
b) supp
Algebra ->
Triangles
-> SOLUTION: The diameter of a ferris wheel is 80 feet.
a) if the ferris wheel make one revolution every 45 seconds, find the linear velocity of a person riding in the ferris wheel.
b) supp
Log On
Question 447049: The diameter of a ferris wheel is 80 feet.
a) if the ferris wheel make one revolution every 45 seconds, find the linear velocity of a person riding in the ferris wheel.
b) suppose the linear velocity of a person riding in the ferris wheel is 8 feet per second. what is the time for one revolution of the ferris wheel.
please show all work so i can understand better Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The diameter of a ferris wheel is 80 feet.
Find the total distance traveled in one revolution, that would be the circumference
;
C = 251.33 ft; distance a person travels in one revolution
:
a) if the ferris wheel make one revolution every 45 seconds, find the linear velocity of a person riding in the ferris wheel.
Using velocity of ft/sec
Velocity = dist/time
v =
v = 5.585 ft/sec is the linear velocity
:
b) suppose the linear velocity of a person riding in the ferris wheel is 8 feet per second. what is the time for one revolution of the ferris wheel.
time = dist/velocity
t = 251.33/8
t = 31.4 sec per revolution
