Question 286027: A triangle has three angles with measurements A, B, and C such that A = x^2 + 49,
B = x + 2, and C = x + 130. Assume all angles are measured in degrees. Find x.
A. x = 0 B. x = 1 C. x = 180 D. x = −1 E. None of these.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A triangle has three angles with measurements A, B, and C such that
A = x^2 + 49, B = x + 2, and C = x + 130.
Assume all angles are measured in degrees. Find x.
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Equation:
A + B + C = 180 degrees
(x^2+49) + (x+2) + (x+130) = 180
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x^2 + 2x + 181 = 180
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x^2 + 2x + 1 = 0
(x+1)^2 = 0
x = -1
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A = x^2+49 = 50 degrees
B = x+2 = 1 degree
C = x + 130 = 129 degrees
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Cheers,
Stan H.
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A. x = 0 B. x = 1 C. x = 180 D. x = −1 E. None of these.
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