SOLUTION: I need help with this problem:
The area of a triange is 90 square feet. The height is 2 less than twice the base. Find the base and height of the triangle.
So, A=90 sq ft
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-> SOLUTION: I need help with this problem:
The area of a triange is 90 square feet. The height is 2 less than twice the base. Find the base and height of the triangle.
So, A=90 sq ft
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Question 21164: I need help with this problem:
The area of a triange is 90 square feet. The height is 2 less than twice the base. Find the base and height of the triangle.
So, A=90 sq ft and the area of a triangle is 1/2 x B x H. The height of my triangle is going to be 2b-2. Here's where the problem is...I don't know what to do next or how to find what my base is. Any help will be great. Thanks!!
Jenny Answer by bonster(299) (Show Source):
You can put this solution on YOUR website! The area of a triange is 90 square feet. The height is 2 less than twice the base. Find the base and height of the triangle.
A=bh
A=90
h=2 less than twice the base
so b=x
and h=2x-2
Plug in what you know (I'll do it one by one)
A=bh
90=bh
90=(x)h
90=(x)(2x-2)
90=()
90=
=0
(x-10)(x+9)=0
x-10=0
x=10
x+9=0
x=-9
if x=10, H=2x-2, 2(10)-2=20-2=18,
h=18, b=10
if x=-9, h=2(-9)-2=-18-2=-20
h=-20, b=-9
but since we know that the height & base cannot have a negative value, "if x=-9" wouldn't work.
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