SOLUTION: In the diagram, Line AB=Line AC, angle A= 60 degrees. If Line AD = 1/4 Line AC, and AE:EB=K:5, find the value of k, with all values in cm. A) 5 B) 2 C) 10 D) 2 1/2 E) 3 1/2

Algebra ->  Triangles -> SOLUTION: In the diagram, Line AB=Line AC, angle A= 60 degrees. If Line AD = 1/4 Line AC, and AE:EB=K:5, find the value of k, with all values in cm. A) 5 B) 2 C) 10 D) 2 1/2 E) 3 1/2       Log On


   



Question 1171816: In the diagram, Line AB=Line AC, angle A= 60 degrees. If Line AD = 1/4 Line AC, and AE:EB=K:5, find the value of k, with all values in cm.
A) 5
B) 2
C) 10
D) 2 1/2
E) 3 1/2
https://ibb.co/K55rshc

Found 2 solutions by math_tutor2020, MathTherapy:
Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

We're given that AB = AC, so triangle ABC is isosceles. This means the base angles B and C are congruent, as they are the base angles. Let y = angle B = angle C.
We're also given angle A is 60 degrees.
So,
A+B+C = 180
60+y+y = 180
2y+60 = 180
2y = 180-60
2y = 120
y = 120/2
y = 60
Each angle of triangle ABC is 60 degrees, so triangle ABC is equilateral.
This tells us that AB = BC = AC.

Draw a line from E to C

We have similar triangles ADE and EDC
This means we can form the proportion
AD/DE = DE/DC
and that can be rearranged into
DE = sqrt(AD*DC)
This shows DE is the geometric mean of AD and DC

Let x = AD
Since AD is 1/4 the length of AC, we know that AC is 4 times longer compared to AD, so AC = 4*AD = 4x
This leads to
AD+DC = AC
x+DC = 4x
DC = 4x-x
DC = 3x

Applying the geometric mean formula gets us
DE = sqrt(AD*DC)
DE = sqrt(x*3x)
DE = sqrt(3x^2)
This simplifies to x*sqrt(3), but we won't need to do this

With AD = x and DE = sqrt(3x^2), we can find AE through the pythagorean theorem
(AD)^2 + (DE)^2 = (AE)^2
(x)^2 + (sqrt(3x^2))^2 = (AE)^2
x^2+3x^2 = (AE)^2
4x^2 = (AE)^2
(AE)^2 = 4x^2
AE = sqrt(4x^2)
AE = sqrt((2x)^2)
AE = 2x

Now we can say
AE+EB = AB
2x+EB = 4x
EB = 4x-2x
EB = 2x
We know that AB = 4x because triangle ABC is equilateral.

The last step is to solve the proportion below
AE:EB = k:5
AE/EB = k/5
(2x)/(2x) = k/5
1 = k/5
k/5 = 1
k = 1*5
k = 5

So AE:EB = k:5 turns into AE:EB = 5:5 and we could reduce that ratio to 1:1
AE:EB = 1:1 indicates AE and EB are the same length.

Answer: A) 5

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

In the diagram, Line AB=Line AC, angle A= 60 degrees. If Line AD = 1/4 Line AC, and AE:EB=K:5, find the value of k, with all values in cm.
A) 5
B) 2
C) 10
D) 2 1/2
E) 3 1/2
https://ibb.co/K55rshc
Let AD be x
Then DC = 3x
With ∡A being 60o, and AD = x, AE/Hypotenuse = 2x
With AC being 4x, AB is also 4x (AC = AB), and since AE = 2x, EB also = 2x
Therefore, as AE:EB = k:5, we get: 2x:2x = k:5
It clearly shows that highlight_green%28matrix%281%2C5%2C+k%2C+%22=%22%2C+5%2C+%22%28CHOICE%22%2C+%22A%29%22%29%29