Question 1001212: D is a point on side BC of a triangle ABC such that A is perpendicular on BC. E is a point on AD for which AE:ED = 5:1.If angle BAD =30 and tan(angle ACB)=6tan(angle DBE),Find angle ACB.
Answer by KMST(5328)   (Show Source):
You can put this solution on YOUR website! I am assuming the problem states that:
D is a point on side BC of a triangle ABC such that AD is perpendicular to BC.
E is a point on AD for which AE:ED = 5:1.
 
In that case, the triangle looks like this:
 Triangles ACD, ABD, and EBD are right triangles, each of them having a right angle at vertex D.
In triangle ABD,
, so  .
In triangle EBD,
 .
In triangle EBD,
 .
 ---> ---> .
So right triangles ABD and ACD are congruent,
meaning that angles  and  are congruent.
Since  , 
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