SOLUTION: Jane drove to her friend Kim's house 29.1 miles away. As she was leaving her house, she noticed that it was exactly 6 pm.
After arriving to Kim's house and spending 1.8 hour there
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-> SOLUTION: Jane drove to her friend Kim's house 29.1 miles away. As she was leaving her house, she noticed that it was exactly 6 pm.
After arriving to Kim's house and spending 1.8 hour there
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Question 985217: Jane drove to her friend Kim's house 29.1 miles away. As she was leaving her house, she noticed that it was exactly 6 pm.
After arriving to Kim's house and spending 1.8 hour there, she looked at the clock and saw that the time now was 8:45 pm.
What was Jane's average speed on her way to Kim's house? Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
Total time elapsed from 6:00 PM to 8:45 PM= 2.75 hrs
Time driving=(total time) - (time at Kim's)=2.75hr-1.8hr=0.95hr
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Average speed=(distance)/(time)=29.1mi/0.95hr=30.6mi/hr
ANSWER: Her average speed was 30.6 MPH.
