SOLUTION: A Jet travels 3285 mi against the wind in 5 hours and 3735 mi with the wind in the same amount of time. What is the rate of the jet in still air and what is the rate of the wind?

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Question 974954: A Jet travels 3285 mi against the wind in 5 hours and 3735 mi with the wind in the same amount of time. What is the rate of the jet in still air and what is the rate of the wind?
Found 2 solutions by solver91311, josmiceli:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!






Solve the 2X2 system for and

John

My calculator said it, I believe it, that settles it

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +s+ = the speed of the jet in still air
Let +w+ = the speed of the wind
+s+-+w+ = the speed of the jet traveling against the wind
+s+%2B+w+ = the speed of the jet traveling with the wind
----------------------------------------------------
(1) +3285+=+%28+s+-+w+%29%2A5+
(2) +3735+=+%28+s+%2B+w+%29%2A5+
------------------------
(1) +3285+=+5s+-+5w+
(2) +3735+=+5s+%2B+5w+
Add the equations
+7020+=+10s+
+s+=+702+
and
(2) +3735+=+5s+%2B+5w+
(2) +747+=+s+%2B+w+
(2) +w+=+747+-+702+
(2) +w+=+45+
The speed of the jet in still air is 702 mi/hr
The speed of the wind is 45 mi/hr
check:
(1) +3285+=+%28+s+-+w+%29%2A5+
(1) +3285+=+%28+702+-+45+%29%2A5+
(1) +3285+=+657%2A5+
(1) +3285+=+3285+
OK
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