Question 957250: At 7h48 George left Windhoek driving to Oshakati (704 km) at an average 105 km/h. At the same time Alex left Oshakati driving to Windhoek at 115 km/h. Where and when did they meet.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! At 7h48 George left Windhoek driving to Oshakati (704 km) at an average 105 km/h.
At the same time Alex left Oshakati driving to Windhoek at 115 km/h.
Where and when did they meet?
:
let t = the traveling time of both George & Alex. (They left at the same time)
When they meet, the sum of their travel distance = 704
Write a distance equation; dist = speed * time
105t + 115t = 704
220t = 704
t = 704/220
t = 3.2 hrs, which is: 3 + .2(60) = 3 hrs 12 min for them to meet
:
7:48 + 3:12 = 11:00 will be the time
:
Find the distance they will meet from Oshakati:
105 * 3.2 = 336 km from Oshakati, Near Tsumeb, I would think
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