SOLUTION: Jane drives straight at 35 mph to her destination. She drives home at 45mph, getting home 11 mins faster than it took her to drive to her destination. What is the total amount of t
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Question 951503: Jane drives straight at 35 mph to her destination. She drives home at 45mph, getting home 11 mins faster than it took her to drive to her destination. What is the total amount of time it took for her round trip? Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! d=distance; t=time for trip
d/35mph-d/45mph=11 min(1hr/60min)
d(1/35mph-1/45mph)=11/60 hr Divide each side by (1/35mph-1/45mph
d=(11/60 hr)/(1/35mph-1/45mph)
d=29.1 mi
29.1 mi/35mph+29.1mi/45mph=t
0.831 hr+0.647 hr=1.478 hr ANSWER: The trip took 1.478 hours.
CHECK
29.1mi/35mph-29.1mi/45mph=11 min
0.831 hr-0.647hr=11 min
0.184 hr(60 min/1 hr)=11 min
11 min=11 min
