SOLUTION: 2motor cyclists travelled from a certain town along the same road, 1 at 50 km/h and the other at 20 km/h. The slower rider set out first and they both arrived at the next town at t

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: 2motor cyclists travelled from a certain town along the same road, 1 at 50 km/h and the other at 20 km/h. The slower rider set out first and they both arrived at the next town at t      Log On

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Question 850286: 2motor cyclists travelled from a certain town along the same road, 1 at 50 km/h and the other at 20 km/h. The slower rider set out first and they both arrived at the next town at the same time. If the distance between the two towns was 10 km, how many min earlier did the slower rider leave?
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
__________________speed________time__________distance
EarlySlow_________20___________k%2Bt___________10
LateFast__________50____________t____________10

The late, fast motorcycle traveled t hours and began after the early motorcycle already traveled for just k hours. Both t and k start as unknown variables.

Travel uniform rates follow RT=D for rate time distance.

SYSTEM TO SOLVE:
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20%28k%2Bt%29=10
-
50t=10
------------------

The system can be simplified before solving:
-------------------
2%28k%2Bt%29=1
-
5t=1
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You can finish the solution.
(BIG HINT: t=1%2F5, substitutable into the simplified 'EarlySlow' equation.)