SOLUTION: Diane will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $55 and costs an additional $0.50 per mile driven. The second plan has

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Diane will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $55 and costs an additional $0.50 per mile driven. The second plan has       Log On

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Question 844711: Diane will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $55 and costs an additional $0.50 per mile driven. The second plan has no initial fee but costs $0.70 per mile driven. How many miles would Diane need to drive for the two plans to cost the same?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = the number of miles she
has to drive for the 2 plans to cost the same
Let +C+ = cost
For the 1st plan:
+C+=+55+%2B+.5x+
For the 2nd plan:
+C+=+.7x+
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Make the costs of the 2 plans the same
+55+%2B+.5x+=+.7x+
+.2x+=+55+
+x+=+275+
Diane needs to drive 275 mi for the two plans to cost the same
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Here is the plot for the 2 plans:
+graph%28+600%2C+400%2C+-50%2C+350%2C+-50%2C+280%2C+.5x+%2B+55%2C+.7x+%29+