SOLUTION: There are 2 cyclists. The first cyclist is traveling at a rate of 6mph. The second cyclist is traveling at a rate of 10mph. If the second cyclist does not leave until 3 hours after
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Question 734218: There are 2 cyclists. The first cyclist is traveling at a rate of 6mph. The second cyclist is traveling at a rate of 10mph. If the second cyclist does not leave until 3 hours after the first cyclist, how long will it take the second cyclist to catch up to the first? Please help me solve this equation. Thank you Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! The 1st cyclist's head start is mi
Start a stopwatch when the 2nd cyclist leaves.
Let = the time on the stopwatch when the
2nd cyclist catches the 1st.
Let = the distance the 2nd cyclist travels
until the 1st is caught.
---------------------
Equation for 1st cyclist:
(1)
Equation for 2nd cyclist:
(2)
--------------
Substitute (2) into (1)
(1)
(1)
(1)
In 4.5 hrs the second cyclist to catch up to the first
check:
(2)
(2)
and
(1)
(1)
(1)
(1)
OK
