SOLUTION: Chris traveled 1 hour longer and 2 miles farther than Calvin, but averaged 3 mph slower.
If the sum of their times was 4 hours, what was the sum in miles of the distances they tra
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-> SOLUTION: Chris traveled 1 hour longer and 2 miles farther than Calvin, but averaged 3 mph slower.
If the sum of their times was 4 hours, what was the sum in miles of the distances they tra
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Question 734161: Chris traveled 1 hour longer and 2 miles farther than Calvin, but averaged 3 mph slower.
If the sum of their times was 4 hours, what was the sum in miles of the distances they traveled? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = Calvin's distance in miles
Let = Calvin's time in hrs
Let = Calvin's speed in mi/hr
------------------------
Calvin's equation:
(1)
Chris's equation:
(2)
----------------------------
given:
Substitute (1) into (2)
(2)
(2)
(2)
(2)
(2)
and
(1)
(1)
(1)
The sum of their distances is miles
check:
(2)
(2)
(2)
(2)
OK
