SOLUTION: Two men are driving. One is travelling 70 mph, and the other is travelling 98 mph. The faster one is 14 miles behind the one that is going 70 mph. How long will it take the faster
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Question 696356: Two men are driving. One is travelling 70 mph, and the other is travelling 98 mph. The faster one is 14 miles behind the one that is going 70 mph. How long will it take the faster one (98mph) to catch up to the slower one (70mph)?
--I tried the problem already and I got 1/2 an hour. I'm unsure though because I'm very uneasy with word problems. Thanks! Found 2 solutions by josmiceli, Alan3354:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Try it this way:
Start a stopwatch when the faster one is
exactly 14 miles behind the slower one.
You will hit the stopwatch when the
faster one has caught the slower one.
Call the time on the stopwatch ( in hours )
----------------------------------------
Let = distance in miles that the slower one
travels until he is caught.
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Equation for slower one:
(1)
Equation for faster one:
(2)
------------------
Substitute (1) into (2)
(2)
(2)
(2)
The faster one catches the slower one
in a half hour.
Looks like you did it right.
You can put this solution on YOUR website! Two men are driving. One is travelling 70 mph, and the other is travelling 98 mph. The faster one is 14 miles behind the one that is going 70 mph. How long will it take the faster one (98mph) to catch up to the slower one (70mph)?
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The faster car is gaining on the other at 28 mi/hr (98 - 70)
t = d/r
t = 14/28 = 1/2 hour
