SOLUTION: A lady drove to a city 30 miles away to shop and returned home in the evening. She spent15 minutes longer driving the return trip than in the going, and she drover three-fourths as

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: A lady drove to a city 30 miles away to shop and returned home in the evening. She spent15 minutes longer driving the return trip than in the going, and she drover three-fourths as      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 669964: A lady drove to a city 30 miles away to shop and returned home in the evening. She spent15 minutes longer driving the return trip than in the going, and she drover three-fourths as fast when returning as she did when going to the city. How long did it take her to drive to the city?
Found 2 solutions by benge2, ankor@dixie-net.com:
Answer by benge2(1) About Me  (Show Source):
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A lady drove to a city 30 miles away to shop and returned home in the evening.
She spent15 minutes longer driving the return trip than in the going, and she
drover three-fourths as fast when returning as she did when going to the city.
How long did it take her to drive to the city?
:
Find the speed first
let s = speed to the city
then
.75s = return speed
:
Change 15 min to .25 hr
:
Write a time equation; time = dist/speed
30%2Fs + .25 = 30%2F%28.75s%29
multiply by 3s, to clear the denominators, results
3(30) + 3s(.25) = 4(30)
90 + .75s = 120
.75s = 120 - 90
.75s = 30
s = 30/.75
s = 40 mph to the city
:
Find the time
30/40 = .75 hrs or 45 min to drive to the city