SOLUTION: Two cars start from the same place at the same time. After two hours, one car has traveled 30% farther than the other. If one car's speed is 20mph larger than the other car's speed

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Question 664912: Two cars start from the same place at the same time. After two hours, one car has traveled 30% farther than the other. If one car's speed is 20mph larger than the other car's speed, what are the speeds of the cars? Solve algebraically
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Distance+=+Speed+%2A+time time = 2
Let the distance of the slower car be d. let the speed of the slower car be s.
You are told the distance of the faster car is 1.3d and its speed is s%2B20
So
d+=+2s remember this for use later
1.3d+=+%28s%2B20%29%2A+2
1.3d+=+2s+%2B+40 use substitution with the value of d above
1.3%282s%29+=+2s+%2B+40
2.6s+=+2s+%2B+40
0.6s+=+40
s+=+66.667 mph
The faster car is going 86.667 (speeding is not kewl)