SOLUTION: Agent S. needs to return in 2 minutes to get picked up. It takes him 1.2 minutes to travel against the wind and 0.8 minutes to travel back with the wind. How fast does he travel

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Question 660993: Agent S. needs to return in 2 minutes to get picked up. It takes him 1.2 minutes to travel against the wind and 0.8 minutes to travel back with the wind. How fast does he travel in still air given the wind is blowing at 2 inches per minute.
All I need is an equation or equations.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +s+ = his speed in still air in in/min
+s+%2B+2+ = his speed in inches/min going with the wind
+s+-+2+ = his speed in inches/min going against the wind
Let +d+ = distance he has to travel
----------------
given:
+s+%2B+2+=+d+%2F+.8+
+s+-+2+=+d+%2F+1.2+
-----------------------
+d+=+.8%2A%28+s+%2B+2+%29+
+d+=+1.2%2A%28+s+-+2+%29+
---------------------------
+.8%2A%28+s+%2B+2+%29+=+1.2%2A%28+s+-+2+%29+
+.8s+%2B+1.6+=+1.2s+-+2.4+
+.4s+=+4+
+s+=+10+
He travels 10 in/min in still air
check:
+s+%2B+2+=+d+%2F+.8+
+12+=+d%2F.8+
+d+=+.8%2A12+
+d+=+9.6+
and
+s+-+2+=+d+%2F+1.2+
+8+=+d+%2F+1.2+
+d+=+1.2%2A8+
+d+=+9.6+
OK