SOLUTION: a high speed bullet train accelerates and decelerates at a rate =6 feet per second square. It's maximum cruising speed =95mi/h. Find the minimum time that the train takes to trave
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-> SOLUTION: a high speed bullet train accelerates and decelerates at a rate =6 feet per second square. It's maximum cruising speed =95mi/h. Find the minimum time that the train takes to trave
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Question 537640: a high speed bullet train accelerates and decelerates at a rate =6 feet per second square. It's maximum cruising speed =95mi/h. Find the minimum time that the train takes to travel between two consecutive stations that are =40 miles apart. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! a high speed bullet train accelerates and decelerates at a rate =6 feet per second square. It's [sic] maximum cruising speed =95mi/h. Find the minimum time that the train takes to travel between two consecutive stations that are =40 miles apart.
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95 mi/hr = 95*22/15 ft/sec = 418/3 ft/sec
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The time to accelerate from 0 to 418/3 at 6 ft/sec/sec = (418/3)/6 seconds
= 209/9 seconds at the start and at the end of the trip.
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Distance traveled in 209/9 seconds = (1/2)*(209/9)*(418/3) times 2
= 83762/27 feet (apx 1618 ft starting, and 1618 stopping)
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40 miles = 211200 feet
211200 - 3236 = 207964 ft @ 418/3 ft/sec --> 1492.56 seconds at cruise
1492.56 + 2*(209/9) = 1539 seconds
= 25' 39"
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I rode the TGV from Paris to Brussels, it goes 345 mi/hr
PS it's = it is
