SOLUTION: An airplane takes five hours to travel a distance of 3600 km against the wind. The return trip takes four hours with the wind. What is the rate of the plane in still air, and what
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: An airplane takes five hours to travel a distance of 3600 km against the wind. The return trip takes four hours with the wind. What is the rate of the plane in still air, and what
Log On
Question 449482: An airplane takes five hours to travel a distance of 3600 km against the wind. The return trip takes four hours with the wind. What is the rate of the plane in still air, and what is the rate of the wind? Thank you for your help! Found 2 solutions by mananth, Alan3354:Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! plane speed = x mph
wind speed = y mph
with wind speed = (x+y)
against wind speed = (x-y)
3600/(x+y)=4
4x+4y=3600
/4
x+y=900....................1
3600/(x-y)=5
3600=5x-5y
x-y=720....................2
Add (1) +(2)
2x=1620
x=810 mph speed of plane
900-810= 90 mph speed of wind
You can put this solution on YOUR website! An airplane takes five hours to travel a distance of 3600 km against the wind. The return trip takes four hours with the wind. What is the rate of the plane in still air, and what is the rate of the wind?
-------------
3600/5 = 720 mph
3600/4 = 900 mph
The airspeed is the average = (720+900)/2 = 810 mph
The windspeed is the difference = 900-810 = 90 mph
