SOLUTION: My probelm is this: A truck enters a highway driving 60mph. A car enters the highway at the same place 12 minutes later and drives 67mph in the same direction. How long before the
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Question 444160: My probelm is this: A truck enters a highway driving 60mph. A car enters the highway at the same place 12 minutes later and drives 67mph in the same direction. How long before the car passes the truck?
I have My Math Lab on coursecompass.com and it kind of explains the solving process but I seem to get lost at the end.
I know that the problem needs to be set up with d(t)=60(t + 10) and d(c)=67t but after that I get lost. Please help. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Truck 60 mph
Car 67 mph
Difference in time=00:12mins 0.2 hours
Truck will have covered 0.2 miles before Car enters the highway
catch up distance= 0.2 miles
catch up speed = 67-60 mph
catch up speed = 7 mph
Catchup time = catchup distance/catch up speed
catch up time= 0.2 / 7
catch up time= 0.03 hours
catch up time= 1.71 minutes
..
The other method
let the car meet after time = t hours
time truck takes = 12 minutes more (t+0.2)hours
Distance same
D= r*t
67*t = 60*(t+0.2)
67t=60t+12
7t= 12
t=12/7
1.71 hours
