SOLUTION: two cyclist start biking from trails start 3 hours apart .the second cyclist btravels at 10 miles per hour and start 3 hours after the first cyclist who is traveling at 6 miles per
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Question 420028: two cyclist start biking from trails start 3 hours apart .the second cyclist btravels at 10 miles per hour and start 3 hours after the first cyclist who is traveling at 6 miles per hour.how much time will pass before the second cyclist catches up with first from the time the second cyclist started baking? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! I cyclist - 6 mph
II cyclist 10 mph
..
In 3 hours cyclist I travels 18 miles: before cyclist II starts.
difference in speed = 10-6 = 4 mph.
catch up speed = 4 mph
catch distance = 18 miles
catch up time = 18 /4 = 4.5 hours.
