Question 414679: During a multi-day camping trip, Terry rowed 17 hours downstream. It took 26.5 hours rowing upstream to travel the same distance. If the speed of the current is 6.8 k/h less than his rowing speed in still water, find his rowing speed and the speed of the current.
t is time, 26.5 and 17
r is rate, r, r-6.8
Distance is the same, so I set the equations equal to each other?
17r = 26.5(r-6.8)
I'm not sure if this is correct, and where I go from here.
Please advise.
Thank you.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! During a multi-day camping trip, Terry rowed 17 hours downstream. It took 26.5 hours rowing upstream to travel the same distance. If the speed of the current is 6.8 k/h less than his rowing speed in still water, find his rowing speed and the speed of the current.
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Downstream DATA:
time = 17 hrs ; rate = r+(r-6.8) km/h ; distance = t*r = 17(2r-6.8) km
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Upstream DATA :
time = 26.5 ; rate = r -(r-6.8) km/h ; distance = t*r = 26.5(6.8) km
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Equation:
distance up = distance down
26.5*6.8 = 17(2r-6.8)
180.2 = 34r-115.6
34r = 295.8
r = 8.7 km/h (rowing speed)
r-6.8 = 1.9 km/h (speed of the current)
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Cheers,
Stan H.
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t is time, 26.5 and 17
r is rate, r, r-6.8
Distance is the same, so I set the equations equal to each other?
17r = 26.5(r-6.8)
I'm not sure if this is correct, and where I go from here
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