SOLUTION: Find the equation of he line passing through (3,0) and (0,-3)

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Question 338093: Find the equation of he line passing through (3,0) and (0,-3)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

First let's find the slope of the line through the points and


Note: is the first point . So this means that x%5B1%5D=3 and y%5B1%5D=0.
Also, is the second point . So this means that x%5B2%5D=0 and y%5B2%5D=-3.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%28-3-0%29%2F%280-3%29 Plug in y%5B2%5D=-3, y%5B1%5D=0, x%5B2%5D=0, and x%5B1%5D=3


m=%28-3%29%2F%280-3%29 Subtract 0 from -3 to get -3


m=%28-3%29%2F%28-3%29 Subtract 3 from 0 to get -3


m=1 Reduce


So the slope of the line that goes through the points and is m=1


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y-0=1%28x-3%29 Plug in m=1, x%5B1%5D=3, and y%5B1%5D=0


y-0=1x%2B1%28-3%29 Distribute


y-0=1x-3 Multiply


y=1x-3%2B0 Add 0 to both sides.


y=1x-3 Combine like terms.


y=x-3 Simplify


So the equation that goes through the points and is y=x-3


Notice how the graph of y=x-3 goes through the points and . So this visually verifies our answer.
Graph of y=x-3 through the points and

If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website.

Jim