SOLUTION: At 7:00 am Joe stats jogging at 6mph. At 7:30 am Ken starts after him. How fast must ken run in order to catch him at 8:00 am? How far did each jog?

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: At 7:00 am Joe stats jogging at 6mph. At 7:30 am Ken starts after him. How fast must ken run in order to catch him at 8:00 am? How far did each jog?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 29089: At 7:00 am Joe stats jogging at 6mph. At 7:30 am Ken starts after him. How fast must ken run in order to catch him at 8:00 am? How far did each jog?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
JOE RUNS 6MPH FOR 1 HOUR AND COVERS 6 MILES
KEN RUNS X MPH FOR .5 HOURS AND COVERS 6 MILES THEREFORE .5X=6 OR X=6/.5 OR
X=12MPH