Question 275234: Please help me solve my equation. Airplan travels 3490km against the wind in 5 hours and 3940 km with the wind in the same amount of time. what is the rate of the plane in still air and what is the wind rate?
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! D=RT
3,490=R*5
R=3,490/5
R=698 KMH IS THE RATE AGAINST THE WIND.
3,940=5*5
R=3,940/5
R=788 KMH IS THE RATE OF THE PLANE WITH THE WIND.
(788-698)/2
90/2=45 KMH IS THE RATE OF THE WIND.
698+45=743 KPH IS THE RATE OF THE PLANE IN STILL AIR.
788-45=743 DITTO.
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