SOLUTION: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 84 miles per hour. Train A passes a stat
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Question 214961: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 84 miles per hour. Train A passes a station at 6:25pm. If train B passes the same station at 6:55pm., at what time will train B catch up to train A? Found 2 solutions by Alan3354, stanbon:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 84 miles per hour. Train A passes a station at 6:25pm. If train B passes the same station at 6:55pm., at what time will train B catch up to train A?
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6:25 PM = 1855
In 1/2 hour from 1825 to 1855, train A goes 40 miles (80 mph * 1/2 hour)
Train B gains on Train A at 4 mph (84-80)
40 miles at 4 mph = 10 hours
1855 + 1000 = 0455
4:55 AM
You can put this solution on YOUR website! ): Train A and B are traveling in the same direction on parallel tracks.
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Train A is traveling at 80 miles per hour and train B is traveling at 84 miles per hour.
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Train A passes a station at 6:25pm. If train B passes the same station at 6:55pm., at what time will train B catch up to train A?
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Train A DATA:
rate = 80 mph ; distance = x miles ; time = d/r = x/80 hrs.
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Train B DATA:
rate = 84 mph ; distance = x miles ; time = d/r = x/84 hrs.
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Comment: Using the station as a start point, Train B starts
1/2 hr. after Train A
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Equation:
A-time - B-time = 1/2 hr
x/80 - x/84 = 1/2
(84x-80x)/(80*84) = 1/2
Cross multiply to get:
2*4x = 80*84
x = 840 (distance traveled from the station before catchup)
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Time = x/84 = 840/84 = 10 hrs for train B to catch train A
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6:55 pm + 10hr = 4:55am
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Cheers,
Stan H.
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