SOLUTION: An arrow is shot vertically upward. Three seconds later, it is at a height of 35m.
What was the initial speed of the arrow?
How long is the arrow in flight from launch to retur
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What was the initial speed of the arrow?
How long is the arrow in flight from launch to retur
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Question 214728: An arrow is shot vertically upward. Three seconds later, it is at a height of 35m.
What was the initial speed of the arrow?
How long is the arrow in flight from launch to returning to the initial height? (Assume the arrow falls vertically downward.)
You can put this solution on YOUR website! An arrow is shot vertically upward. Three seconds later, it is at a height of 35m.
What was the initial speed of the arrow?
:
Using the equation -4.9t^2 + vt + c = H
Where
h = height after t seconds (35 meters)
t = time in seconds (3)
-4.9t^2 = the downward pull of gravity
v = upward velocity
c = initial height (0 in this problem)
:
-4.9(3)^2 + 3v = 35
-4.9(9) + 3v = 35
-44.1 + 3v = 35
3v = 35 + 44.1
3v = 75.1
v =
v = 26.37 m/sec initial velocity
:
How long is the arrow in flight from launch to returning to the initial height? (Assume the arrow falls vertically downward.)
-4.9t^2 + 26.37t = 0
Factor out -4.9t
-4.9t(t - 5.38) = 0
Two solutions
t = 0 sec; arrow on it's way
t = 5.38 sec when it returns to earth (time of flight)
