SOLUTION: I am having trouble figuring out how to solve this problem and any help would be appreciated. This problem is not from a text book and is one that my professor create himself.
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Question 214298: I am having trouble figuring out how to solve this problem and any help would be appreciated. This problem is not from a text book and is one that my professor create himself.
A speedy tortoise can run with a speed of 10 cm/sec and a hare can run 20 times as fast. If they both start at the same time, but the hare stops for 2 minutes to rest, the tortoise wins by 20cm.
1. How long does the race take?
2. What is the length of the race? Found 2 solutions by stanbon, scott8148:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A speedy tortoise can run with a speed of 10 cm/sec and a hare can run 20 times as fast. If they both start at the same time, but the hare stops for 2 minutes to rest, the tortoise wins by 20cm.
1. How long does the race take?
Tortoise DATA:
rate = 10 cm/sec ; distance = x cm ; time = x/10 seconds
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Hare DATA:
rate = 200 cm/sec ; distance = (x-20) cm ; time = (x-20)/200 sec
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Equation
Hare time + 120 seconds = tortoise time
(x-20)/200 + 120 = x/10
Multiply thru by 200 to get:
x-20 + 200*120 = 20x
19x = 200*120 -20
x = 1262.11 cm (length of the race)
x/10 = 126.21 seconds (time of the race)
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Cheers,
Stan H.
2. What is the length of the race?
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