SOLUTION: Cindy and Dave left the dock to canoe downstream. Fifteen minutes later Tammy left by otorboat with the supplies. Since the motorboat traveled twice as fast as the anoe, it caught
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Question 205607This question is from textbook Algebra structure and method
: Cindy and Dave left the dock to canoe downstream. Fifteen minutes later Tammy left by otorboat with the supplies. Since the motorboat traveled twice as fast as the anoe, it caught up with the canoe 3km from the dock. What was the speed of the motorboat? This question is from textbook Algebra structure and method
You can put this solution on YOUR website! Cindy and Dave left the dock to canoe downstream. Fifteen minutes later Tammy
left by motorboat with the supplies.
Since the motorboat traveled twice as fast as the canoe, it caught up with the
canoe 3km from the dock.
What was the speed of the motorboat?
;
Speed will be in km/hr; change 15 min to .25 hrs
:
Let s = the motor boat speed
then
.5s = speed of the canoe)
:
Write time equation: (time =
:
Motor time + 15 min = Canoe time + .25 =
Multiply equation by s, results
3 + .25s = 2(3)
;
3 + .25s = 6
:
.25s = 6 - 3
s =
s = 12 km/h motorboat speed
:
:
Check solution, find the travel times
3/6 = .5 hrs
3/12= .25 hrs
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diff = .25 hrs (15 min)
