Question 197236: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 120 miles per hour. Train A passes a station at 2.20 A.M. If train B oases the same station at 2:35 A.M., at what time will train B catch up to train A?
I honestly don't know where to begin solving this.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 120 miles per hour. Train A passes a station at 2.20 A.M. If train B oases the same station at 2:35 A.M., at what time will train B catch up to train A?
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Draw the picture of the two trains moving in the same direction.
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Train A DATA:
rate = 100 mph ; time = x hrs ; distance = rt = 100x miles
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Train B DATA:
rate = 120 mph ; time = x - (1/4) hr. ; distance = rt = 120x - 30 miles
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Equation:
distance A = distance B
100x = 120x - 30
20x = 30
x = 3/2 hrs
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Meeting time: 2:20 + 1 hr 30 min = 3:50
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Cheers,
stan H.
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