Question 147375: A fishing boat traveled 3 hours against a 6 km/hr current. The return trip took only 2 hours. Find the speed of the boat in still water. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A fishing boat traveled 3 hours against a 6 km/hr current. The return trip took only 2 hours. Find the speed of the boat in still water.
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Against current DATA:
Time = 3 hrs ; rate = b-6 : distance = tr = 3(b-6) = 3b-18 km
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With current DATA:
Time = 2 hrs ; rate = b+6 ; distance = tr = 2(b+6) = 2b+12 km
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EQUATION:
distance with = distance against
2b+12 = 3b-18
b = 30 kph (speed of the boat in quiet water)
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Cheers,
Stan H.