SOLUTION: A tennis ball is dropped from 1.47 m above the ground. It rebounds to a height of 0.989 m. With what velocity does it hit the ground? The acceleration of gravity is 9.8 m/s^2

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Question 1165531: A tennis ball is dropped from 1.47 m above the
ground. It rebounds to a height of 0.989 m.
With what velocity does it hit the ground?
The acceleration of gravity is 9.8 m/s^2
. (Let
down be negative.)
Answer in units of m/s.

Answer by ikleyn(52864) About Me  (Show Source):
You can put this solution on YOUR website!
.

Write the mechanical energy conservation law


    mgh = %28mv%5E2%29%2F2.


Cancel the mass "m" in both side and get


    gh = v%5E2%2F2.


From this formula


    v = sqrt%282gh%29 = sqrt%282%2A9.8%2A1.47%29 = 5.368 m/s.    ANSWER