SOLUTION: Edward takes 15 minutes longer than Kate does to make the 112-mile drive between two cities. Kate drives 8 miles an hour faster. How fast do Edward and Kate drive?
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Question 1162900: Edward takes 15 minutes longer than Kate does to make the 112-mile drive between two cities. Kate drives 8 miles an hour faster. How fast do Edward and Kate drive? Found 5 solutions by jim_thompson5910, amarjeeth123, ikleyn, josgarithmetic, MathTherapy:Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
x = time in hours it takes Kate to make the drive
x+0.25 = time in hours it takes Edward to make the drive
15 minutes = 1/4 hour = 0.25 hours
y = Edward's speed in miles per hour (mph)
y+8 = Kate's speed in mph
For Edward,
distance = rate*time
112 = y*(x+0.25)
which solves to
y = 112/(x+0.25)
You can put this solution on YOUR website! Let Edward's speed be s.
Let Kate's speed be s+8.
Distance=112 miles
Time=Distance/speed
Edward's time=112/s
Kate's time=112/(s+8)
(112/s)=(1/4)+(112/(s+8))
112(32)=s(s+8)
s^2+8s-3584=0
Solving we get s=56
Edward's speed is 56 mph and Kate's speed is 64 mph respectively.
Let x be the Edward's rate driving, in miles per hour.
Then the Kate's rate driving is (x+8) mph.
Write the "time" equation
- = of an hour.
To solve it, multiply both sides by 4x*(x+8). You will get
112*4*(x+8) - 112*4*x = x*(x+8)
112*4(x+8) - 112*4x = x*(x+8)
3584 = x*(x+8) (*)
From this point, there are two ways to complete the solution.
First way is to solve this quadratic equation formally.
In this way, you will get the ANSWER 56 mph for Edwards and 64 mph for Kate.
The other way is to introduce new variable y = x+4.
Then x+8 = y-4, and your equation (*) takes the form
3584 = (y-4)*(y+4)
3584 = y^2 - 16
3584 + 16 = y^2
3600 = y^2
y = 60
and you get the same answer practically MENTALLY.
You can put this solution on YOUR website! Edward takes 15 minutes longer than Kate does to make the 112-mile drive between two cities. Kate drives 8 miles an hour faster. How fast do Edward and Kate drive?
Let Edward's speed be S
Then Kate's is: S + 8
We then get the following TIME equation:
112(4)(S + 8) = 112(4)(S) + S(S + 8) ------ Multiplying by LCD, 4S(S + 8)
(S - 56)(S + 64) = 0
Edward's speed or OR S = - 64 (ignore)
Can you now find Kate's speed?