SOLUTION: 2 ships leave the same port simultaneously. One ship sails 450 nautical miles on a bearing of 068 degrees, while the other ship sails 600 nautical miles on a bearing of 215 degrees
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Question 1112946: 2 ships leave the same port simultaneously. One ship sails 450 nautical miles on a bearing of 068 degrees, while the other ship sails 600 nautical miles on a bearing of 215 degrees. How far apart are the ships then, correct to the nearest nautical mile. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! 2 ships leave the same port simultaneously.
One ship sails 450 nautical miles on a bearing of 068 degrees, while
the other ship sails 600 nautical miles on a bearing of 215 degrees.
How far apart are the ships then, correct to the nearest nautical mile.
:
Find the angle (A) between the paths of the two ships
215 - 68 = 147 degrees
A triangle is formed by the paths of the two ships and the distance between them (a)
Use the law of cosines
a^2 = 450^2 + 600^2 - 2(450*600)*cos(147)
a^2 = 202500 + 360000 - 2(270000)*-.83867
a^2 = 562500 - (540000 * -.83867)
a^2 = 562500 + 452882
a =
a = 1008 miles apart
