Question 1087510: The Boeing 747-8 Intercontinental Jet can carry approximately 422,000 gallons of gasoline, making it possible for the jet to travel 14,430 kilometers before needing to refuel.
Use a linear model to predict the amount of gasoline that is present on the Jet after it has been in flight for 18 hours without stopping to refuel. In two or more complete sentences, explain your answer.
(0,422,000) (1, 369, 250) 422,000 - 369, 250 over 0-1 = 52,750/1=52,750
(2, 316,500) (3, 263,750) 315,500-263,750/3-2=52,750-1=52,750 (4, 211,000) (5, 158,250) 211,000-158,250/5-4=52,750/1=52,750 and (6, 105,500) (7, 52,750) 105,500-52,750/7-6=53,750/1=52,750
The y axis = Gasoline in Jet (In Gallons) and it goes like this goes 0, 50,000; 100,000; 150,000; 200,000; 250,000; 300,000, 350,000; 400,000 and 450,000
On the graph it had this:
a point on y axis for 422,000
On the x axis Flight Time (in Hours) are for the hours 2 the point is on 369,250
On hour 4 the point is 316,500
On hour 6 the point is on 263,750
On hour 8 this point is on 211,000
On hour 10 the point is on 158,250
On the 12 hour the point is on 105,500
On the 14 hour the point is on 52,750
and on the 16th hour the point is on 26,375
But I was trying to figure for the 18th hour and how much fuel it will take/use and I can't get it to come out right an get all these figures to cordinate into the graph I did which did not come out the way it should
Gallons Gallons 2 Hours
(422,250 - 316,500 ) = 52,750 422,000
(316,250 - 263,750) = 52,750 369,250 2
(211,00 - 158,250) = 52,750 316,500 4
(105,500 - 52,750) = 52,750 263,750 6
211,000 8
158,250 10
105,500 12
52,750 14
16
18
I cab paste it on here because it didn't copy onto here to show what happened not even a screen shot I need help to figure when in flight for 18 hours and fuel it used without refueling and I need help in how to graph all this with points on every 2 hour mark and fuel used.
Answer by ikleyn(52832)   (Show Source):
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