SOLUTION: If you drop an object off the top of the MahaNakhon tower, the height (in feet) it is from the ground after x seconds is given by the equation h = 2,012 – 12x^2. At what height fr
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Question 1063934: If you drop an object off the top of the MahaNakhon tower, the height (in feet) it is from the ground after x seconds is given by the equation h = 2,012 – 12x^2. At what height from the ground is the object after 5 seconds?
You can put this solution on YOUR website! Sub 5 for x, find h.
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Most places on Earth are subject to ~ 32 ft/sec/sec acceleration due to gravity.
--> -16t^2, not 12.
