SOLUTION: A train travels 25 km/h faster than a bus. The train takes 3 hours less then the bus to travel 1500 km. How long will it take for the train to travel the 1500 km?

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Question 1060817: A train travels 25 km/h faster than a bus. The train takes 3 hours less then the bus to travel 1500 km. How long will it take for the train to travel the 1500 km?
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52802) About Me  (Show Source):
You can put this solution on YOUR website!
.
A train travels 25 km/h faster than a bus. The train takes 3 hours less then the bus to travel 1500 km.
How long will it take for the train to travel the 1500 km?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Let "x" be the train speed, in km/h.

Then the bus speed is (x-25) km/h.

The train covers 1500 km in 1500%2Fx hours.

The bus does it in 1500%2F%28x-25%29 hours.

The condition  says

1500%2F%28x-25%29 - 1500%2Fx = 3.

Multiply both sides by x*(x-25). You will get

1500 x - 1500(x-25) = 3x(x-25),

3x^2 - 75x - 37500 = 0,

x^2 - 25x - 12500 = 0,

x%5B1%2C2%5D = %2825+%2B-+sqrt%2825%5E2+%2B4%2A12500%29%29%2F2 = %2825+%2B-+225%29%2F2.

Only positive root makes sense: x = 250%2F2 = 125.

Thus you found that the train speed is 125 km/h.
Then the bus speed is 125-25 = 100 km/h.

Answer.  How long will it take for the train to travel the 1500 km? - 1500%2F125 = 12 hours.


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
A train travels 25 km/h faster than a bus. The train takes 3 hours less then the bus to travel 1500 km. How long will it take for the train to travel the 1500 km?
Let time train takes to travel 1,500 miles be T
Then time bus takes is: T + 3
Speed of train = %221%2C500%22%2FT, and speed of bus = %221%2C500%22%2F%28T+%2B+3%29
We then get the following SPEED equation: matrix%281%2C3%2C+%221%2C500%22%2FT%2C+%22=%22%2C+%221%2C500%22%2F%28T+%2B+3%29+%2B+25%29
1,500(T + 3) = 1,500T + 25T(T + 3) ------ Multiplying by LCD, T(T + 3)
1500T+%2B+4500+=+1500T+%2B+25T%5E2+%2B+75T
25T%5E2+%2B+1500T+%2B+75T+-+1500T+-+4500+=+0
25T%5E2+%2B+75T+-+%224%2C500%22+=+0
25%28T%5E2+%2B+3T+-+180%29+=+25%280%29
T%5E2+%2B+3T+-+180+=+0
(T - 12)(T + 15) = 0
T, or time train takes = highlight_green%28matrix%281%2C2%2C+12%2C+hours%29%29 OR T = - 15 (ignore)