SOLUTION: A motor boat travels 204km in 4 hours going upstream. It travels 252km going downstream in the same amount of time. What is the rate of the boat in still water and what is the rate

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: A motor boat travels 204km in 4 hours going upstream. It travels 252km going downstream in the same amount of time. What is the rate of the boat in still water and what is the rate      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1027003: A motor boat travels 204km in 4 hours going upstream. It travels 252km going downstream in the same amount of time. What is the rate of the boat in still water and what is the rate of the current?
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
A motor boat travels 204 km in 4 hours going upstream. It travels 252 km going downstream in the same amount of time.
What is the rate of the boat in still water and what is the rate of the current?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

204%2F4 = 51 km%2Fhour is the motor boat' speed relative to river's banks floating upstream.

It is the difference of the speed of the motor boat in still water "u" and the current speed "v". 
So you have this equation 

u - v = 51.    (1)


Next, 252%2F4 = 63 km%2Fhour is the motor boat' speed relative to river's banks floating downstream.

It is the sum of the speed of the motor boat in still water "u" and the current speed "v".
So you have the second equation 

u + v = 63.    (2)

Hence, you need to solve the system of equation (1) and (2) to find "u" and "v":

u - v = 51.    (1')
u + v = 63.    (2')

Every time, when you see the system like this, add the equations (both sides). You will get

2u = 51 + 63  --->  2u = 114  --->  u = 114%2F2 = 57.

It is the speed of the motor boat in still water, 57 km%2Fhour. 

Now from (2) v = 63 - u = 63 - 57 = 6 km%2Fh is the speed of current.